We have an implicit function $f(x,y,z)$ defining a volume. The surface is defined by $f(x,y,z)$ and we can generate either a point cloud or voxels at uniform intervals. How to use this data to reconstruct a mesh surface?
Let $S$ be a set of vertices ${p_1, p_2, \dots}$.
The Voronoi region $v_i$ of $p_i$ is defined as \(\nu_i = \{ x \in \mathbb{R}^d \mid \pi_i(x) \leq \pi_j(x), \forall p_j \in S\}\) i.e. the set of all points closer to $p_i$ than to any other point in $S$.
Intersections of all the bisected spaces between every 2 points.
The Voronoi cell is the intersection of the Voronoi regions of vertices in subset $X \subseteq S$. \(\nu_X = \bigcap_{p_i \in X} \nu_i\) The Voronoi complex of $S$ is the set of all of all of its Voronoi cells (all non-empty faces of $S$). \(\nu_S = \{\nu_X \mid X \subseteq S, \nu_X \neq \emptyset \}\)
Empty circumdisk: No point $p \in S$ lies in the interior of any Delaunay triangle’s circumcircle.
A Delaunay Complex is defined as such \(D_S = \{ \text{convexHull}(X) \mid \nu_X \in \nu_S\}\) No $d+2$ points are spherical if the Voronoi Complex is in $\mathbb{R}^d$. (e.g. in 2D space we will get a quad.)
A Delaunay edge is added between 2 vertices $p_i,p_j$ only if the Voronoi cell $\nu_{ij}$ intersects the surface of the implicitly defined mesh (usually can identify by checking if $f(u)f(v) < 0$, where $u,v$ are the extreme points of the Voronoi cell).
For each Voronoi cell, if it intersects the surface as a topological ball, then the RDT is homeomorphic to the surface
Isosurfaces are the surfaces where all the points on that surface are of a certain value.
At fixed intervals the implicit equation is computed with those coordinates to generate a scalar field, on which we can run Marching Squares/Cubes algorithm to reflect the separation at the isosurface (change in values on that scalar field).
$2^8$ combinations of black/white assigning of vertices in a cube.
However only 22 unique ones, the rest are all symmetries
Many ambiguities: caused by hole formation and/or symmetrical division.